0
It depends on the function that is used to generate the sequence - and there are infinitely many of them.
One possible generators is
t(n) = 10n2 - 90n + 200 where n = 1, 2, 3, ...
If that is the case, the next number is 0.
But, if I wanted to have the next number as 20, I could re-define the generating function as:
t(n) = (10n3 - 30n2 - 160n + 540)/3 where n = 1, 2, 3, etc.
Give me any fourth number and I can give you a cubic polynomial that will generate that sequence.
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