Let the integers be m and n.
∴ By the condition given in the question,
m + n - mn = 72
∴ m + n - mn = 71 + 1
∴ m + n - mn - 1 = 71
∴ (m - 1)(1 - n) = 71
∴ (m - 1)(1 - n) = 1 × 71 = 71 × 1 = (-1) × (-71) = (-71) × (-1)
Case 1:
m - 1 = 1 and 1 - n = 71
∴ (m, n) = (2, -70)
Case 2:
m - 1 = 71 and 1 - n = 1
∴ (m , n) = (72, 0)
This case is inadmissible as m, n are non zero integers.
Case 3:
m - 1 = -1 and 1 - n = -71
∴ (m , n) = (0, 72)
This case is inadmissible as m, n are non zero integers.
Case 4:
m - 1 = -71 and 1 - n = -1
∴ (m, n) = (-70, 2)
But as the given expression is symmetric, therefore, (2, -70) and (-70, 2) cannot be considered two different pairs.
∴ We get only one solution.
Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.
1 and 40, 2 and 20 others include: 4 and 10 5 and 8 so there aren't just two, their are four pairs of integers whose product is 40.
The factor pairs of 15 are (15,1)(5,3) Neither of them add up to 11. No integers fulfill your request.
(-91,1)(-13,7)(91,-1)(13,-7)
Not quite. A rational number is a ratio and each rational number is a ratio of specific pairs of integers - not ANY two integers. And, of course, 0 is not allowed on the denominator.
Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.
1 and 40, 2 and 20 others include: 4 and 10 5 and 8 so there aren't just two, their are four pairs of integers whose product is 40.
The factor pairs of 15 are (15,1)(5,3) Neither of them add up to 11. No integers fulfill your request.
If restricted to integers, the answer is 1 - for any prime number.
(-91,1)(-13,7)(91,-1)(13,-7)
Not quite. A rational number is a ratio and each rational number is a ratio of specific pairs of integers - not ANY two integers. And, of course, 0 is not allowed on the denominator.
The factor pairs of 855 are (855,1)(285,3)(171,5)(95,9)(57,15)(45,19) None of them add up to 98.
There are an infinite number of prime numbers which are consecutive odd integers. Choose any natural number n. Take all primes up to any number n, take their product, and add 1 and subtract 1 from it. These 2 numbers are consecutive odd integers. eg 2*3*5*7 = 210 209 and 211 are primes which are consecutive odd integers.
Three pairs of integers alone have this property: 12 and 1; 2 and 6; and 3 and 4. There are infinitely many non-integer pairs also.
Factor pairs refer to integers, not decimals.
The only pair of integers are 1 and 61. But you could multiply 10 and 6.1 or an infinite number of pairs of numbers.
A single number does not have a product. there are infinitely many pairs (or sets of more numbers) whose product is 21. For example, 210 and 0.1