Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.
The simplest rule, based on a polynomial of order 5, is
Un = (-4n5 + 75n4 - 510n3 + 1665n2 - 2306n + 1440)/120 for n = 1, 2, 3, ...
Another possibility is a Fibonacci-like sequence with
U1 = 3, U2 = 4 and Un+2 = Un + Un+1 for n = 1, 2, 3, ...
Adding consecutive odd numbers
The number is 1.
65/18 as a mixed number is 3 and 11/18
47 4+7 = 11 7+11 = 18 11+18=29 18+29=47
10 and 11/18
Adding consecutive odd numbers
18 over 11 as a mixed number = 17/11
36, possibly. The sequnce being *2, *2, -6, *2, *2, -6 etc
11/18 cannot be simplified - 11 is a prime number !
-18 is less than -11 or -18 < -11
7 + 11 = 18 11 + 18 = 29 18 + 29 = 47 Add the two previous terms together.
Oh, what a delightful pattern you've discovered! It looks like each number is increasing by adding the next odd number, starting from 1. So, 2 + 1 = 3, 3 + 3 = 6, 6 + 5 = 11, and 11 + 7 = 18. Keep exploring these patterns, my friend, and let your creativity flow!
The number is 1.
65/18 as a mixed number is 3 and 11/18
No.
If you mean 4 11 18 25 then the next number is 32 because the numbers are increasing by increments of 7
47 4+7 = 11 7+11 = 18 11+18=29 18+29=47