Given any number it is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question and the next is the given number. There are also non-polynomial solutions.
The simplest rule, based on a polynomial of order 5, is
Un = (-4n5 + 75n4 - 510n3 + 1665n2 - 2306n + 1440)/120 for n = 1, 2, 3, ...
Another possibility is a Fibonacci-like sequence with
U1 = 3, U2 = 4 and Un+2 = Un + Un+1 for n = 1, 2, 3, ...
To find the next number in the series, we can observe the alternating pattern between pairs of numbers. The first number is 14, and it decreases by 3 to 11, then increases by 7 to 18. Following this pattern, the next number after 18 should decrease by 2, resulting in 16. Therefore, the next number in the series is 16.
Adding consecutive odd numbers
65/18 as a mixed number is 3 and 11/18
The number is 1.
47 4+7 = 11 7+11 = 18 11+18=29 18+29=47
To find the next number in the series, we can observe the alternating pattern between pairs of numbers. The first number is 14, and it decreases by 3 to 11, then increases by 7 to 18. Following this pattern, the next number after 18 should decrease by 2, resulting in 16. Therefore, the next number in the series is 16.
Adding consecutive odd numbers
18 over 11 as a mixed number = 17/11
36, possibly. The sequnce being *2, *2, -6, *2, *2, -6 etc
11/18 cannot be simplified - 11 is a prime number !
Oh, what a delightful pattern you've discovered! It looks like each number is increasing by adding the next odd number, starting from 1. So, 2 + 1 = 3, 3 + 3 = 6, 6 + 5 = 11, and 11 + 7 = 18. Keep exploring these patterns, my friend, and let your creativity flow!
7 + 11 = 18 11 + 18 = 29 18 + 29 = 47 Add the two previous terms together.
-18 is less than -11 or -18 < -11
If you mean 4 11 18 25 then the next number is 32 because the numbers are increasing by increments of 7
65/18 as a mixed number is 3 and 11/18
The number is 1.
No.