203
5 of them with a remainder of 1
3s + 1
3118 in between 3s each number is just 21 added to the previous number: 55,76,97,118,139,160,etc.
12 1/3s is 12/312/3 = 4
4 3s = 4*3 = 12, which is a rational number.
203
They're both the same number.
5 of them with a remainder of 1
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
your browning with the prefix 3s indicates it was made in 1963.
123 does not belong because it isn't in the 3s multiplication 31 does not belong because it isn't in the 3s multilplication
2
The answer depends on which of the two 3s in the number you are referring to!
A 3s orbital is associated with more energy than a 2s orbital. This is because the principal quantum number (n) is higher for the 3s orbital compared to the 2s orbital, resulting in higher energy levels.
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The easiest way is to "flip" the inequality symbol end divide by the negative number:Example:6 < 3 - 3s6 - 3 < 3 - 3s -33 < -3s Method a) Divide by negative coefficient and flip the inequality symbol3/-3 > -3s/-3-1 > s or s< -13 < -3s Method b) Full algorithm, eliminate -3s by adding 3s on both sides3 +3s < -3s + 3s3 + 3s < 03 - 3 + 3s < 0 -33s < -33s/3 < -3/3s < -1 Looks familiar? So basically if you perform the full algorithm (method b) you can understand why we flip the inequality symbol when we have to eliminate a negative coefficient but it is faster just to flip the symbol (method a)