There are infinitely many of them. Consider 5.51. Then between 5.5 and 5.51 there is 5.503. And between 5.5 and 5.503 there is 5.500002 and so on. For ever.
Chat with our AI personalities
50. 51. 52. 53. 54. 55. That is 6 numbers.
53 and 55.
It is: 55C6 = 28,989,675
I am not stupid enough to try and list them since there are 55*54*53*52*51*50/(6*5*4*3*2*1) = 28,989,675 combinations. nPr=permutation while nCr=combination. The question is how many combination of 6 are there in 55 numbers. So the answer should be based on the formula: nPr = n!/(n-r)! where ! is factorial and nCr = nPr/r! = n!/{(n-r)*r!} ; So using the formula should look likr this 55C6 = 55!/{(55-6)!*6!} = 55!/(49!*6!) = 28,989,675
They are the infinite number of rational numbers between 0 and +6