It is 0.000404
The odds of being dealt three suited sevens in a six-deck game are approximately 63,000 to 1. [Source: Arnold Snyder, "The Big Book of Blackjack" p205] The odds of being dealt three sevens (not suited) is somewhat worse than 500 to 1 (considering that casinos frequently offer the payout of 500 to 1 for players receiving three unsuited 7s in the "Super Sevens" side bet).
The answer depends on what game you are playing and so how many cards you are dealt!
It depends on the blackjack variation that you are playing -- it can be played with as few as 1 deck and as many as 8 decks. Since- and double-deck games are dealt by hand, while games with 4, 6, and 8 decks are dealt from a shoe. In general, the higher the number of decks that are used corresponds to more liberal betting options available to a player. For example, in a single-deck game, players can double on 9, 10, or 11 only, while in an 8 deck game, the player can double on any two cards. Also, many casinos have moved to paying 6-5 for a single-deck blackjack, while continuing to pay 3-2 for a blackjack from a 4, 6, or 8 deck game.
There are 2 ways to get blackjack...You can be dealt an ace first:4/52 are Aces, then 16 out of the remaining 51 cards are 10, J, Q or K4/52 X 16/51 = .0241Or you can be dealt a face card first:16/52 are face cards, then 4 out of the remaining 51 cards are Aces16/52 X 4/51 = .0241So your answer is .0241 + .0241 = .0482 or 4.82%
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
The odds of being dealt three suited sevens in a six-deck game are approximately 63,000 to 1. [Source: Arnold Snyder, "The Big Book of Blackjack" p205] The odds of being dealt three sevens (not suited) is somewhat worse than 500 to 1 (considering that casinos frequently offer the payout of 500 to 1 for players receiving three unsuited 7s in the "Super Sevens" side bet).
The last card - the Ace - has a special value in Blackjack. It can count as either 1 or 11, with the actual number being dependent on what helps out the most with a particular hand. Being dealt an Ace and any face card is an automatic Blackjack and the player will be paid out 3:2 immediately.
I believe the name "blackjack" may have come from the fact that originally players were paid extra when they were dealt a spade-suited blackjack with an Ace and Jack.
if the blackjack is a natural i.e. you get 21 from the first deal, then no. But if the 5-card charlie comes after you have been dealt 3 or more cards, then yes
You'd win $300... Unless you are dealt a blackjack, in which case you'd receive $450 at 3:2 odds, or $360 with 6:5 odds.
The answer depends on what game you are playing and so how many cards you are dealt!
It depends on the blackjack variation that you are playing -- it can be played with as few as 1 deck and as many as 8 decks. Since- and double-deck games are dealt by hand, while games with 4, 6, and 8 decks are dealt from a shoe. In general, the higher the number of decks that are used corresponds to more liberal betting options available to a player. For example, in a single-deck game, players can double on 9, 10, or 11 only, while in an 8 deck game, the player can double on any two cards. Also, many casinos have moved to paying 6-5 for a single-deck blackjack, while continuing to pay 3-2 for a blackjack from a 4, 6, or 8 deck game.
The answer depends on how many cards you are dealt!
Assuming blackjack values, there are seven cards per suit that can be dealt first that could lead to a total of 19. Each of these has one card per suit to be dealt next to make 19, except an 8 has two. If it's a standard 4-deck situation, the odds are: (6/13)(16/207) + (1/13)(32/207) = 128/2691
There are 2 ways to get blackjack...You can be dealt an ace first:4/52 are Aces, then 16 out of the remaining 51 cards are 10, J, Q or K4/52 X 16/51 = .0241Or you can be dealt a face card first:16/52 are face cards, then 4 out of the remaining 51 cards are Aces16/52 X 4/51 = .0241So your answer is .0241 + .0241 = .0482 or 4.82%
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
hypergeometric distribution: f(k;N,n,m) = f(5;52,13,5)