To calculate the osmolarity of a 5.5% glucose solution, first convert the percentage to grams per liter: 5.5% means 5.5 grams of glucose per 100 mL, which is 55 grams per liter. Glucose (C6H12O6) has a molar mass of approximately 180 g/mol, so 55 grams corresponds to about 0.306 moles per liter (55 g / 180 g/mol). Since glucose does not dissociate in solution, the osmolarity is equal to its molarity, which is approximately 0.306 osmoles per liter.
Ten percent of 55 is 5.5.
55 percent = 55/100 = 11/20
"Percent" is the same as "of 100" so the answer is 5.5
110 is 55 percent of 200.
55%
Ten percent of 55 is 5.5.
55 percent = 0.55 or 55/100 or 11/20
30 percent of 55 is 16.5.
The volume of alcohol in the solution is 110.0 ml, calculated by multiplying the volume of the solution (200.0 ml) by the alcohol by volume percentage (55%).
73 percent of 55 = 40.1573% of 55= 73% * 55= 0.73 * 55= 40.15
205 percent of 55 = 112.75205% of 55= 205% * 55= 2.05 * 55= 112.75
What percent is 5 out 55
55 percent = 55/100 = 11/20
55 Percent of 231 = 55/100 * 231 = 127.05.
39% of 55% = 0.2145
"Percent" is the same as "of 100" so the answer is 5.5
What percent is 5 out 55