To calculate the osmolarity of a 5.5% glucose solution, first convert the percentage to grams per liter: 5.5% means 5.5 grams of glucose per 100 mL, which is 55 grams per liter. Glucose (C6H12O6) has a molar mass of approximately 180 g/mol, so 55 grams corresponds to about 0.306 moles per liter (55 g / 180 g/mol). Since glucose does not dissociate in solution, the osmolarity is equal to its molarity, which is approximately 0.306 osmoles per liter.
Ten percent of 55 is 5.5.
55 percent = 55/100 = 11/20
"Percent" is the same as "of 100" so the answer is 5.5
110 is 55 percent of 200.
55 percent of anything is 55 per one-hundred. That is what percent means, per one-hundred. 55 per one-hundred is 55/100, which equals 0.55 55 percent of 70 = 0.55 x 70 0.55 x 70 = 38.5 55 percent of 70 is 38.5
Ten percent of 55 is 5.5.
55 percent = 0.55 or 55/100 or 11/20
The volume of alcohol in the solution is 110.0 ml, calculated by multiplying the volume of the solution (200.0 ml) by the alcohol by volume percentage (55%).
30 percent of 55 is 16.5.
73 percent of 55 = 40.1573% of 55= 73% * 55= 0.73 * 55= 40.15
205 percent of 55 = 112.75205% of 55= 205% * 55= 2.05 * 55= 112.75
55 percent = 55/100 = 11/20
What percent is 5 out 55
55 Percent of 231 = 55/100 * 231 = 127.05.
39% of 55% = 0.2145
"Percent" is the same as "of 100" so the answer is 5.5
What percent is 5 out 55