42.5 m/85 cm = 4250 cm/85 cm = 50 pieces.
Perimeter = 2*(4m + 85cm) = 2*4.85 m = 9.7 m
p=wholesale price, m=markup p*m*(1-.15)=p*1.19 m*.85=1.19 m=1.19/.85=1.40 His markup must be at least 40%.
85 cubed = 85 ^ 3 = 85 * 85 * 85 = 614,125
85 times 6 equals 510
K3PO4 is a basic compound. It is the potassium salt of phosphoric acid, which makes it a strong base in solution.
85*2+m
The chemical formula for potassium phosphate is K3PO4.
The compound name for K3PO4 is potassium phosphate.
85 m = 85000 mm
The empirical formula for K3PO4 is K3PO4 itself. This is because the subscripts in the formula (3 for potassium, 1 for phosphorus, and 4 for oxygen) represent the simplest whole-number ratio of the elements in the compound.
The osmolarity of a 2 M solution of calcium chloride is 6 osm/L. This is because calcium chloride dissociates into three ions in solution (Ca2+ and 2Cl-) leading to a total of 3 osmoles of particles in solution for every 1 mole of calcium chloride dissolved.
Normal saline does not significantly affect plasma osmolarity as it has the same osmolarity as extracellular fluid. When administered intravenously, the body quickly equilibrates the saline with the surrounding fluids, maintaining overall osmolarity.
Osmolarity is calculated by multiplying the molarity of a solute by the number of particles it forms in solution (i.e., its van 't Hoff factor). The formula for osmolarity is osmolarity = molarity × van 't Hoff factor.
85 cents, usually.
Potassium phosphate (K3PO4) contains the following atoms:Potassium (K, from kalium)Phosphorus (P)Oxygen (O)
Osmolarity, which is also known as osmotic concentration, is the measure of solute concentration. The osmolarity of a solution is usually expressed by Osm/L (pronounced "osmolar").