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Curie: A unit of radioactivity equal to 3.7 � 10^10 Disintegrations (decays) per second.
It will take 25.0898 minutes, approx.
The decay rate N at time t is N(t)=N(0) x 2^-(t/t_half), where t_half is the half life and N(0) is the decay rate at t=0. The ^ means "to the power of."You can solve this for t_half:t_half = - t / log_2(N(t)/N(0)) (log_2 means logarithm base 2)N(350 minutes)=1250, N(0)=8540. The rest is just finding a calculator to give you log_2 of 1250/8540.
Yes. Think of a function that starts at the origin, increases rapidly at first and then decays gradually to an asymptotic value of 0. It will have attained its asymptotic value at the start. For example, the Fisher F distribution, which is often used, in statistics, to test the significance of regression coefficients. Follow the link for more on the F distribution.