There are infinitely many possible patterns.
One pattern is the polynomial or order 5:
t(n) = (-n^5 + 11n^4 - 75n^3 - 241n^2 - 344n + 192)/24 for n = 1, 2, 3, ...
There are also also non-polynomial solutions.
Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
In fact, this is the Fibonacci sequence which is defined by:
t(1) = 1
t(2) = 2
and
t(n) = t(n-2) + t(n-1) for n = 3, 4, 5, ...
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
The sequence 112358 follows the Fibonacci pattern, where each number is the sum of the two preceding numbers. Starting with 1 and 1, the next numbers are calculated as follows: 1+1=2, 1+2=3, 2+3=5, resulting in the sequence 1, 1, 2, 3, 5, 8. This pattern continues indefinitely.
Add the previous 2 numbers to get the next number.
The prime numbers from 1 to 3 are 2 and 3.
The numbers are what you get when you make a sum of reciprocal exponents. N(1) = 1^1 = 1 N(2) = 1^2 + 2^1 = 1 + 2 = 3 N(3) = 1^3 + 2^2 + 3^1 = 1 + 4 + 3 = 8 N(4) = 1^4 + 2^3 + 3^2 + 4^1 = 1 + 8 + 9 + 4 = 22 The next number in the pattern would be 2780.
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
12 ****************************** 11, 16, 22 are the 3 numbers continuing the pattern.
The sequence 112358 follows the Fibonacci pattern, where each number is the sum of the two preceding numbers. Starting with 1 and 1, the next numbers are calculated as follows: 1+1=2, 1+2=3, 2+3=5, resulting in the sequence 1, 1, 2, 3, 5, 8. This pattern continues indefinitely.
Add the previous 2 numbers to get the next number.
You add the 2 numbers before e.g. 2+3=5
81 then 243
The factors of these numbers are: 1 1, 2 1, 3 1, 2, 3, 6 1, 3, 9
Yes. For example, the average of the numbers 1, 2, and 3 is 2. 1+2+3=6 6/3=2
The numbers are 1, 2, 3, 6.
It is a pattern. Go up two numbers, go down two numbers.
The prime numbers from 1 to 3 are 2 and 3.
The numbers are what you get when you make a sum of reciprocal exponents. N(1) = 1^1 = 1 N(2) = 1^2 + 2^1 = 1 + 2 = 3 N(3) = 1^3 + 2^2 + 3^1 = 1 + 4 + 3 = 8 N(4) = 1^4 + 2^3 + 3^2 + 4^1 = 1 + 8 + 9 + 4 = 22 The next number in the pattern would be 2780.