Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 4 such that the first four numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
For example,
If you want the next number to be 1: try the rule
t(n) = (-4*n^4 + 40*n^3 - 134*n^2 + 188*n - 87)/3.
If you want 2, try t(n) = (-5*n^4 + 50*n^3 - 167*n^2 + 234*n - 108)/4
If you want 6, try t(n) = (-9*n^4 + 90*n^3 - 299*n^2 + 418*n - 192)/8
The simplest rule, based on a polynomial of order 3, is
t(n) = 2*n^2 - 4*n + 3 and accordingly, the next number is 33.
The pattern is this: The number before, plus itself plus 2. For example: 1 (number)+ 0 (number berfore)+ 2 (always use a two in this pattern) = 3 then 1+3+2=6 then 3+6+2+11 and 6+11+2=19, which is your pattern. So the answer is 11+19+2=32. Now the pattern is 1,3,6,11,19,32 Thats a wrap.
19 + 3 = 22 to repeat the pattern
If you eliminate the first number, the rest are prime and the next one would be 29.
The pattern appears to be increasing by multiplying by 3 and then adding 1. Starting with 1, the next number would be 1 x 3 + 1 = 4, then 4 x 3 + 1 = 13, and so on. Therefore, the next number in the pattern would be 40 x 3 + 1, which equals 121.
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
The pattern is this: The number before, plus itself plus 2. For example: 1 (number)+ 0 (number berfore)+ 2 (always use a two in this pattern) = 3 then 1+3+2=6 then 3+6+2+11 and 6+11+2=19, which is your pattern. So the answer is 11+19+2=32. Now the pattern is 1,3,6,11,19,32 Thats a wrap.
21 and 13. The pattern is t(n) = (-n4 + 10n3 - 23n2 + 38n - 12)/12
19 + 3 = 22 to repeat the pattern
If you eliminate the first number, the rest are prime and the next one would be 29.
The pattern seems to be +1 +3 +1 +3 (3+1 = 4, 4+3 = 7, 7+1 = 8, etc...) So next in the sequence would be 12.
7 is the next number in the pattern
131. The rule is Un = (8n3 - 36n2 + 64n - 27)/3 for n = 1, 2, 3, ...
7. The pattern is adding 9 and separating the digits into single numbers: 10, 19, 28, 37.
5 8 7 10 9 12 11 14 The pattern is +3, -1, +3, -1, +3, -1, +3
what are the next numbers in the pattern 1, 2, 3, 5, 8, 13,_,_
N, N+1, (N+1) + 4, (N+1) + 4 + 1, Repeat Next numbers are 19, 23, 24
The progression is any number in the pattern x 3 + 11 x 3 + 1 = 44 x 3 + 1 = 1313 X 3 + 1 = 4040 X 3 + 1 = 121121 x 3 + 1 = 364.......which is the next number in the pattern. See? Easy as pi; which is:3.14159265...