A square has equal length sides, so each side is 13 in. The perimeter is the distance of the 4 sides added together. The perimeter is: 13 + 13 + 13 + 13; which is 52 in.
Each side = 52/4 = 13 cm Area = 13*13 = 169 square cm
perimeter_of_square = 4 x side ⇒ side = perimeter ÷ 4 = 52 cm ÷ 4 = 13 cm area_of_square = side2 = (13 cm)2 = 169 cm2
Perimeter = 4*13 = 52 units of measurment
It is: 4*13 = 52 inches
A square has equal length sides, so each side is 13 in. The perimeter is the distance of the 4 sides added together. The perimeter is: 13 + 13 + 13 + 13; which is 52 in.
Each side = 52/4 = 13 cm Area = 13*13 = 169 square cm
13 feet
Each side measures: 52/4 = 13 cm Area = 13*13 = 169 square cm
52 ÷ 4 = 13 feet each four sides
The sides of square are equal,and when they have given you the area and asked for perimeter,it means that you have to look for the square root of the area which will be one side and that is 13.perimeter=side ×4 which is 13×4=52.
Oh, what a lovely problem to solve! Since the perimeter of the square is 52 cm, we can divide that by 4 to find the length of each side, which is 13 cm. To find the area of the square, we simply square the length of one side, so the area is 169 square cm. It's wonderful to see how math can help us discover the beauty in shapes!
4*13 = 52 cm.
A paralallogram with a perimeter = 13 units can be made to "lean" over until its area becomes 5 square units.Also:A rectangle with a long side of 5.608495283 and a short side of 0.8915047169 will have a perimeter of 13 units and an area of 5 square units.Also:An isosceles triangle with say 2 legs of 5.5943 and the 3rd leg of 1.8114 will have a perimeter of 13 units and an area of 5 square units.So the answer is that there are many shapes that will satisfy the perimeter and area given.
perimeter_of_square = 4 x side ⇒ side = perimeter ÷ 4 = 52 cm ÷ 4 = 13 cm area_of_square = side2 = (13 cm)2 = 169 cm2
When a square paper is folded vertically to form a rectangle with a perimeter of 39 inches, the length of the rectangle is 19.5 inches (half of the perimeter). Since the length of the rectangle is the same as the side length of the original square, the area of the original square can be calculated as the square of the side length, which is 19.5 inches squared, equaling 380.25 square inches.
Let x be the side of the triangle. Thus 4(x-5) is the perimeter of the square.Balance by the perimeter relation,3x = 7+4(x-5)Solve for x,x = 13 inches