If the shape measuring 8 centimeters by 5 centimeters is a rectangle, the perimeter of the rectangle is 25 centimeters (2w + 2l)
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
The answer is 12 cm.
20 cm
Perimeter = sum of three sides = 96 cm One side of 34cm, another of 25 cm so the third is 96 - 34 -25 = 37 cm
58 cm
If the shape measuring 8 centimeters by 5 centimeters is a rectangle, the perimeter of the rectangle is 25 centimeters (2w + 2l)
20
To find the width of the rectangle, we need to subtract twice the length from the perimeter. Given that the length is 25 centimeters and the perimeter is 84 centimeters, twice the length would be 50 centimeters. Subtracting 50 from 84 gives us a width of 34 centimeters for the rectangle.
Perimeter: 12+25+12+25 = 74 meters
Its perimeter is 48 centimeters (4X12=48).
The answer is 12 cm.
20 centimeters.
20 cm
It could be a regular pentagon
20 cm
12 in.