First off this would not be a square at all. . . this is more of a rectangle. Perimeter of that figure would be as follows:
P=8(4)+10(4)+4(4)
I'll leave you to crunch the numbers.
Two and Four are both common denominators of Four and Eight, therefore either of these can be used. You would need only two 4ft square tiles or eight 2ft square tiles to cover the 4ft x 8ft floor.
Each side would be 8ft, so 32ft in perimeter.
4ft * 8ft = 32 sqft = 2.9729 sq metres (to 4 dp)
If the room is 8ft by 10ft then it is 80 square feet; just multiply length by width.
Area of any triangle: 0.5*base*height
5ft*8ft, 4ft*10ft, and 2ft*20 ft
Perimeter=24ft
P { margin-bottom: 0.21cm; } (8ft x 10ft = 80ft2) Therefore: 80ft² = 7.4322m²
10+8+6=24ft
4ft X 14ft X 8ft
First, multiply 2 feet times 4 feet or 4 feet plus 4 feet. The answer is 8 feet.
8*10 = 80 square feet.
Two and Four are both common denominators of Four and Eight, therefore either of these can be used. You would need only two 4ft square tiles or eight 2ft square tiles to cover the 4ft x 8ft floor.
Each side would be 8ft, so 32ft in perimeter.
4ft * 8ft = 32 sqft = 2.9729 sq metres (to 4 dp)
32 square feet. Multiply length by width - the result is the area in square feet.
How many sq m is 8ft by 8ft?