An octagon has 8 sides, thus the equation would be 8 x 7 = 56. So the perimeter would be 56 yards.
Perimeter = 5*8 = 40 yards
The area of a regular hexagon can be calculated using the formula: ( \text{Area} = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem} ). For a hexagon with a side length of 8.1 yards, the perimeter is ( 6 \times 8.1 = 48.6 ) yards. Plugging in the values, the area is ( \frac{1}{2} \times 48.6 \times 7 = 170.1 ) square yards. Thus, the area of the hexagon is 170.1 square yards.
The perimeter ( P ) of a rectangle is given by the formula ( P = 2 \times (length + width) ). If the perimeter is 312 yards, we can set up the equation ( 312 = 2 \times (length + width) ), simplifying to ( length + width = 156 ) yards. The actual dimensions can vary, but for example, if the length is 80 yards, the width would be 76 yards (since ( 80 + 76 = 156 )).
It is: 2*(9.5+4) = 27 yards
65 yards
Perimeter = 5*8 = 40 yards
A regular pentagon has a perimeter of 5s. We set this equal to 15, and solve for s, and convert to yards.5s = 15s = 33 feet converted to yards is 3/3 = 1 yard.
Perimeter = 4*4.8 = 19.2 yards
None. 42 yards is a length with no width. Therefore it cannot have a perimeter.
A decagon has 10 sides. If it is a regular decagon, all of the sides are the same length. Each side would be 0.8 yards or 2.4 feet in length.
The perimeter is the total distance around - width + width+ length + length.
The area of a regular hexagon can be calculated using the formula: ( \text{Area} = \frac{1}{2} \times \text{Perimeter} \times \text{Apothem} ). For a hexagon with a side length of 8.1 yards, the perimeter is ( 6 \times 8.1 = 48.6 ) yards. Plugging in the values, the area is ( \frac{1}{2} \times 48.6 \times 7 = 170.1 ) square yards. Thus, the area of the hexagon is 170.1 square yards.
Length + width = half of perimeter so width = p/2 - length ie (22-12) 10 yards.
The perimeter ( P ) of a rectangle is given by the formula ( P = 2 \times (length + width) ). If the perimeter is 312 yards, we can set up the equation ( 312 = 2 \times (length + width) ), simplifying to ( length + width = 156 ) yards. The actual dimensions can vary, but for example, if the length is 80 yards, the width would be 76 yards (since ( 80 + 76 = 156 )).
20 yds
Since a square has four sides of equal length, divide the perimeter measurement by four: 300 / 4 = 75 yards.
It is: 2*(9.5+4) = 27 yards