Best Answer

Double the area and find 2 numbers that have a sum of 42.5 and a product of 375 which will work out as 30 and 12.5 by using the quadratic equation formula.

Therefore the diagonals are of lengths 30 and 12.5 which will intersect each other half way at right angles forming 4 right angle triangles inside the rhombus with sides of 15 cm and 6.25 cm

Using Pythagoras' theorem each out side length of the rhombus is 16.25 cm and so 4 times 16.25 = 65 cm which is the perimeter of the rhombus.

Q: What is the perimeter of a rhombus whose diagonals add up to 42.5 cm and has an area of 187.5 square cm showing work?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.

The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2

Each side S = square root ( 152 + 202 ) = 25The perimeter will then be 4 x S = 100

No. If they were equal the rhombus would become a square.

Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.

Related questions

Area of the rhombus: 0.5*7.5*10 = 37.5 square cm Perimeter using Pythagoras: 4*square root of (3.75^2 plus 5^2) = 25 cm

No. The diagonals of a rhombus are perpendicular only if the rhombus is a square.

noNo, the diagonals of a rhombus are perpendicular to each other.Unless the rhombus is regular (and called a square) the diagonals are of different lengths.

The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2

If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.

Each side S = square root ( 152 + 202 ) = 25The perimeter will then be 4 x S = 100

Square, rhombus or a kite.

No. If they were equal the rhombus would become a square.

Perimeter = 29 cm so each side is 7.25 cm. The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm. Therefore, the area of the rhombus is twice that = 49.7 square cm.

Perimeter: 4 times square root of (3.5^2+6^2) = 2 times square root of 193 in cm

Rhombus and Square (since a square is just a "special" rhombus, with right angles)

"Congruent" isn't used to describe the diagonals of a rhombus. However, all four sides of a rhombus are congruent - they are all the same length.The diagonals of a rhombus are perpendicular to each other. They are not the same length - if the diagonals were the same length, then you would have a square.