It is: (4.9*pi)/2 + 4.9 = 12.597 m rounded to 3 decimal places
You refer to a "rectangular" bottom, but we know that a circle offers the most area for a given perimeter, so the height of the rectangular part should be 0. We really just want a semicircle with a perimeter of 12 meters.π·d/2 + d = 12 m(π/2 + 1)·d = 12 md = 12 m / (π/2 + 1) = ~4.6678 m
The area of a semicircle can be calculated using the formula ( A = \frac{1}{2} \pi r^2 ), where ( r ) is the radius. Given a diameter of 20 m, the radius is ( r = \frac{20}{2} = 10 ) m. Plugging this into the formula, the area is ( A = \frac{1}{2} \pi (10)^2 = 50\pi ) square meters, which is approximately 157.08 square meters.
153.94 sq. m.radius = diameter/2 = 14/2 = 7metersFormula: Area of circle = radius2 * pi=72 *π= 49πsubstitute pi = 3.1416= 49 * 3.1416= 153.94 sq. m.
Perimeter = 490 cm + 9.8 m + 6.5 m = 21.2 m
Perimeter = 7+7+12+12 = 38 m
circumference or perimeter of the semi-circle = (diameter*pi)/2 + diameter
401.92 m
Perimeter means circumference which is 2 times Pi. That would be 10 times 3.14 which is 31.4 m.
You refer to a "rectangular" bottom, but we know that a circle offers the most area for a given perimeter, so the height of the rectangular part should be 0. We really just want a semicircle with a perimeter of 12 meters.π·d/2 + d = 12 m(π/2 + 1)·d = 12 md = 12 m / (π/2 + 1) = ~4.6678 m
The area of a semicircle can be calculated using the formula ( A = \frac{1}{2} \pi r^2 ), where ( r ) is the radius. Given a diameter of 20 m, the radius is ( r = \frac{20}{2} = 10 ) m. Plugging this into the formula, the area is ( A = \frac{1}{2} \pi (10)^2 = 50\pi ) square meters, which is approximately 157.08 square meters.
Perimeter: 32 m Area: 60 m
153.94 sq. m.radius = diameter/2 = 14/2 = 7metersFormula: Area of circle = radius2 * pi=72 *π= 49πsubstitute pi = 3.1416= 49 * 3.1416= 153.94 sq. m.
Perimeter = 490 cm + 9.8 m + 6.5 m = 21.2 m
Perimeter = 7+7+12+12 = 38 m
Its perimeter is: 7+6+7+6 = 26 m
perimeter or circumference = 2*pi*7 m
Perimeter of rectangle: 2*(7+6) = 26 m