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Q: What is the perimeter of a square that is 8 times the length of 1 side minus 24 inches?

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24 inches

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

In geometry, Heron's (or Hero's) formula, named after Heron of Alexandria, states that the area A of a triangle whose sides have lengths a, b, and c is square root of semi perimeter multiply by semi perimeter minus a multiply by semi perimeter minus b multiply by semi perimeter minus c.

The square root of minus 8 is equal to the square root of 8 times the square root of minus 1, or 2.8284i.

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Related questions

24 inches

Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]

Do-it-in-your-head method: 1. Length + width is half the perimeter ie 116 in 2. 116 minus 68 is 48, half of 48 is 24 which is the width, making the length 92 in

Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)

The length is (18 centimeters) minus (the width)

If it's a rectangle, just minus the length from the perimeter twice and than divide what you have by 2. Width = (Perimeter - (length*2))/2

Perimeter = Width x 2 + length x 2. To find width, you minus the length from perimeter because opposite of ADD is SUBTRACT.

For a regular four-sided figure, area divided by length or half the perimeter minus the length.

Perimeter minus two times the width will give you the two times the length. Area is found by multiplying the length by the width.

In geometry, Heron's (or Hero's) formula, named after Heron of Alexandria, states that the area A of a triangle whose sides have lengths a, b, and c is square root of semi perimeter multiply by semi perimeter minus a multiply by semi perimeter minus b multiply by semi perimeter minus c.

93

To be perfectly correct about it, a perimeter and an area can never be equal.A perimeter has linear units, while an area has square units.You probably mean that the perimeter and the area are the same number,regardless of the units.It's not possible to list all of the rectangles whose perimeter and area are thesame number, because there are an infinite number of such rectangles.-- Pick any number you want for the length of your rectangle.-- Then make the width equal to (double the length) divided by (the length minus 2).The number of linear units around the perimeter, and the number of square unitsin the area, are now the same number.

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