An equilateral triangle with sides of 9 meters, silly!
Perimeter is 2l+2w, so 10+6 is 16 metres
32 meters. (8 meters x 4 sides)
perimeer of the triangle = sum of all the sides = 18 +18+11= 47 cm hence perimeter is 47 cm
The room measures 16 meters x 8 meters and has a diagonal measurement of 17.9 meters.
8 meters
An equilateral triangle with sides of 9 meters, silly!
4330.127 m2
Perimeter is 2l+2w, so 10+6 is 16 metres
Let the sides of the smaller triangle be x:- x = (983/3)-105 x = 222 and 2/3 meters or 222.666 .... recurring
32 meters. (8 meters x 4 sides)
perimeer of the triangle = sum of all the sides = 18 +18+11= 47 cm hence perimeter is 47 cm
In effect an equilateral triangle is made up of two right angle triangles joined together so use Pythagoras' theorem to find the height:- 182-92 = 243 and the square root of this will be the height of the equilateral triangle which is about 15.588 cm
If you wanted to find the distance, you would just add 1.2+1.2+1.2=3.6. Since the triangle is equilateral, all sides will be equal.
The room measures 16 meters x 8 meters and has a diagonal measurement of 17.9 meters.
Each side measures 18 meters.
There is no simple answer to the question. The information provided in the question is sufficient to determine that the base has an area of 41 square metres. But the shape of the base is indeterminate. It could be an equilateral triangle with a perimeter of 29.2 metres or a polygon with a very large number of sides and a perimeter of 22.7 metres. There are many intermediate solutions.