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Let's first reformat it:

x2 + y2 - 12x - 8y - 43 = 0

x2 - 12x + 36 + y2 - 8y + 16 = 43 + 36 + 16

(x - 6)2 + (y - 4)2 = 95

So this equation defines a circle, with a center point at (6, 4) and a perimeter (i.e. circumference) of √95.

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Q: What is the perimeter of the curve x2 plus y2-12x-8y-43 equals 0?
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