The largest angle then will be 94.35 degrees opposite the longest sides of 162cm and by using the sine rule of 120/sin(94.35) = b/sinB = c/sinC the perimeter of the triangle works out as 381.83cm rounded to two decimal places.
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Its longest side of 162cm is opposite to its biggest angle which is 94.54 degrees and by using the sine rule its other sides are 98.34cm and 121.49cm. Therefore perimeter of the triangle is: 162+98.34+121.49 = 381.83cm
Using the sine rule in trigonometry the perimeter of the triangle is 381.83 cm and its area is 5956.67 square cm both rounded to two decimal places
Using the sine rule a/A = b/B = c/B the perimeter of the triangle works out as 382.02 cm with an area of 5965.8 square cm rounded to one decimal place.
how do you construct a triangle which has a perimeter of 120 and the base angles abc be 30 and 45 degrees
The sum of the 3 interior angles of any triangle ... no matter how large or small ... is always 180 degrees. This rule has no connection to the perimeter of the triangle. The perimeter may be one inch, less than one inch, 10 miles, more than 1,000 miles, etc., and the sum of the interior angles is always the same 180 degrees.