1st equation: 3x+2y = 2
2nd equation: x-3y = -14
Multiply all terms in the 2nd equation by 3 and subtract it from the 1st equation:-
So: 11y = 44 or y = 4
By substitution point of intersection is at: (-2, 4)
The intersection is (-2, 6)
(4, -7)
It works out that they intersect at: (4, -7)
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
The intersection is (-2, 6)
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
(4, -7)
It works out that they intersect at: (4, -7)
By a process of elimination and substitution the lines intersect at: (4, -7)
By a process of elimination and substitution the lines intersect at: (1/4, 0)
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
2
The coordinates of the point of intersection is (1,1).
When x = -2 then y = 4 which is the common point of intersection of the two equations.