The outcome is that you have pulled a marble out of the bag.
The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.
The sample space for pulling marbles out of a bag containing 6 red, 3 yellow, 1 black, and 1 green marble, when drawing 2 at a time, consists of all possible combinations of two marbles. Each combination can include two marbles of the same color or one marble of different colors. For example, possible outcomes include (red, red), (red, yellow), (yellow, green), and so on. The total number of combinations can be calculated using combinatorial methods, but the sample space itself includes all unique pairs of the marbles.
It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.
It depends on whether their is those colors of marbles in the bag, and how many of each, and if so you have to put it into ratios or percents and the one with the larger number is the one with the greater chance... sincerely, Grade 8 Student....in Canada
There would be a 7/19 or 36.84% chance of drawing a blue marble from the bag.
The first marble is the independent event because its probability is only based on the sample space of the bag. The second marble is the dependent event because its probability is based on the sample space of the bag which has now been changed by the first marble.
well sort of you see if she only has green cubes then it is impossible for her to pick blue. so the outcome is 14 out of 14.
Two.
The odds of pulling a red marble on the first try is 4/15 or about .27 and the probability of drawing a white marble the second time if a the first is a red marble is 5/14 or about .36. the odds of both happening is the product of the probabilities of the other events, or 2/21.
The probability of pulling a red or yellow marble out of a bag of 3 green 8 red 8 yellow and 3 black marbles is 16 out of 22, or about 0.73.
cinnamon!!!
2/6
The numerator is the number of possible successful outcomes. The denominator is the total number of possible outcomes, successful or not . . . 2 for a coin toss, 36 for a pair of dice, 46 for pulling one marble out of a bag with 46 marbles in it, 29 for naming one date in a leap February, etc.
The sample space of an experiment would be the set of all possible outcomes. If you are reaching your hand into a bag and pulling out a marble at random, the outcomes will either be (red)(red)(yellow)(yellow)(yellow)(yellow)(yellow). This gives seven different options. This will obviously change each time a marble is removed or added.
3/6 * 3/5 = 6/30 or 1/5 so you have a 20% chance of pulling a white and then black marble.
It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.
You would be more likely to pull out a white marble as there are no red marbles in the bag.