Wiki User
∙ 11y agoPower = energy used/time to use it
Power of this CD player = 60,000/(30 x 60) = 331/3 watts
That solution doesn't depend on the player's efficiency ... you specified
only the energy it uses.
But since you did mention the concept of efficiency, I'm compelled to add a
thought here: If you're describing the kind of CD player that you can carry
in your pocket and listen to it on the bus, then 33 watts is an astronomical
power consumption for it. You'd need to carry a back-pack full of batteries,
and recharge them every few hours.
If these are real figures, and the thing really does consume 33 watts in normal
use, then I hope it plugs into the wall, and drives a nice pair of speakers.
Wiki User
∙ 11y ago.33
Assuming that juels is your attempt to spell joules, the answer is 1 newton-metre.
The box acquires (75 x 2.5) = 187.5 joules of gravitational potential energy.The efficiency of your effort is (187.5 / 425) = 44.1% (rounded)
3 Kilowatts is a measure of electrical power and means the wind turbine produces 3,000 joules per second. So the question is fairly meaningless, assuming the wind is at the right speed it will be producing 3kW every second, every hour and every day!
Power input = 700 WEfficiency = 75% so power output = 75% of 700 = 525 W Time = 30 seconds => Work done = 525W * 30s = 15750 W.s = 15750 Joules = 15.75 kiloJoules.
25 percent
25 percent
25%
Efficiency is measured in joules.
The efficiency of the machine can be calculated by dividing the useful work output by the total input energy and multiplying by 100. In this case, the efficiency would be (35/100) * 100 = 35%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
.33
Efficiency is typically measured as the ratio of useful energy output to the total energy input, expressed as a percentage. In terms of joules, the efficiency can be calculated as the useful energy output in joules divided by the total energy input in joules, multiplied by 100. This calculation helps assess how effectively a system converts energy input into useful output.
The efficiency of the lever can be calculated as the ratio of the output work to the input work, multiplied by 100% to express it as a percentage. In this case, the efficiency would be 870 joules (output work) divided by 930 joules (input work), multiplied by 100% which equals 93.55%.
Here you must calculate 1 / 0.365.
25 percent