It is: 2*5*11 = 110
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110
110 55,2 11,5,2 2 x 5 x 11 = 110
110 is an even number; therefore, it's divisible by 2. Indeed, 110/2 = 55. 55 ends with the number 5, and so must be divisible by 5, which it is; 55/5 = 11. We now have three factors for 110: 2, 5, and 11. All three of those numbers are prime numbers, so we're done. Thus the prime factorization of 110 is 2 X 5 X 11.
The prime factors of 110 are 2x5x11.
110 55,2 11,5,2
Exponents are not needed but it would be 21 x 51 x 111
55 3*55 = 165 2*55 = 110
It is: 2*5*11 = 110
The tree for 110 is: 55 & 2. 2 is prime. Then 5 & 11. They are both prime.
2 x 5 x 11 = 110
2 x 5 x 11 = 110
2×5×11
110 = 2 x 5 x 11
The prime factorization of 110 is 2 x 5 x 112 x 5 x 11 = 110As a product of its prime factors: 2*5*11 = 110
2 x 5 x 11 = 110
110 55,2 11,5,2 2 x 5 x 11 = 110