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Since '125' ends in '5' it will divide by '5' , a Prime number.

Hence

5)125) =

5)25 =

5)5 = 1

When reduced to '1' , the division process is complete.

So the factors are '5', '5' & '5'.

Hence this would be written explonential form as 5^(3) = 125

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lenpollock

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Wiki User

11y ago

It is: 5*5*5 = 125 or as 53 = 125

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Q: What is the prime factorization of 125 using a factor tree?
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