all the numbers are prime numbers
therefore the prime factorization of 2*2*5*11=2*2*5*11
110 55,2 11,5,2 2 x 5 x 11 = 110
23 is already prime.
13 is already prime. Just write it down.
It is: 2*2*5*7 = 140 by dividing it by each prime number that has no remainder
48 24,2 12,2,2 6,2,2,2 3,2,2,2,2
24 12,2 6,2,2 3,2,2,2
110 55,2 11,5,2 2 x 5 x 11 = 110
23 is already prime.
456
13 is already prime. Just write it down.
18 9,2 3,3,2
60 30,2 15,2,2 5,3,2,2
Divide by 3 or 5. 3 x 5 = 15
As a product of its prime factors: 2*2*2*5*19 = 760
Yes, 2x2x2x5 can be written in prime factorization as 2^3 x 5. In prime factorization, we break down a number into its prime factors. Here, 2 is a prime number and appears three times, so we write it as 2^3. The number 5 is also a prime number and appears once, so we simply write 5.
It is: 2*2*5*7 = 140 by dividing it by each prime number that has no remainder
Multiply the factors. They should equal the original number.