76 is an even number so it is divisible by 2, so 2 is the first prime factor.
76/2 = 38, and 38 is an even number divisible by 2, so 2is the next prime factor.
38/2 = 19, and 19 is a Prime number, so 19 is the next prime factor.
The prime factorization of 76 is 2 x 2 x 19.
The factors of 76 are 1, 2, 4, 19, 38, and 76. The prime factorization is 2 x 2 x 19.
2*2*19 = 76
You have to find the smallest prime number that can go into 76, which is 2 and find out what 76/2 is. The, you would have to take the non-prime number and find the smallest prime number that can go into that, and divide by those to numbers again. The prime number you had with 76, you would keep that and keep dividing the non-prime numbers until you end up with all prime numbers.
I can't draw a factor tree here 76 / 2 = 38 38 / 2 = 19 Prime factorization is 2, 2, 19
23 is already prime.
The prime factorization of 76 is 2 x 2 x 19
19x2x2
76 = 2 * 2 * 19
As a product of its prime factors: 2*2*19 = 76 or as 22*19 =76
The prime factors are: 2, 19
22 x 19 = 76
76 = 2 x 2 x 19
22*19 = 76
76 = 2 x 2 x 19
76
The factors of 76 are 1, 2, 4, 19, 38, and 76. The prime factorization is 2 x 2 x 19.
76 38,2 19,2,2 2 x 2 x 19 = 76