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In the range of 1 to 10, there are five odd numbers: 1, 3, 5, 7, and 9. Since there are a total of 10 numbers, the probability of selecting an odd number is the number of odd outcomes divided by the total outcomes. This gives us a probability of 5/10, which simplifies to 1/2 or 50%.

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1mo ago

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What Selecting a random digit from 0 to 9 and getting Ann odd number or a prime number find the probability using Venn diagram?

To find the probability of selecting an odd number or a prime number from the digits 0 to 9, we first identify the relevant sets. The odd numbers in this range are {1, 3, 5, 7, 9}, while the prime numbers are {2, 3, 5, 7}. The intersection of these sets, containing the odd prime numbers, is {3, 5, 7}. Using a Venn diagram, we can visualize the total unique outcomes: there are 8 favorable outcomes (odd: 5 + prime: 4 - intersection: 3) out of 10 total digits. Therefore, the probability is 8/10, or 0.8.


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