11/19 or just under 58 % it will be red, just under 16 % of the time it will be blue and a little over 26 % it will be green
The probability of drawing a green ball from a collection that only contains red and blue balls is 0%. Since there are no green balls present in the selection, it is impossible to draw one, making the probability zero.
There is a probability of 3 that it will be blue.
100%
The probability is 19/25 * 18/24 = 0.57
No comment
3/8
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
Yes, those events can be found.
To find the probability of getting either blue or green, we need to know the total number of outcomes. If there are 310 green items and 15 blue items, the total is 310 + 15 = 325. The probability of getting either blue or green is then the number of favorable outcomes (blue + green) divided by the total outcomes, which is (310 + 15) / 325 = 325 / 325 = 1, or 100%.
The probability of drawing a green ball from a collection that only contains red and blue balls is 0%. Since there are no green balls present in the selection, it is impossible to draw one, making the probability zero.
There is a probability of 3 that it will be blue.
The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).
100%
The probability is 0.56
This is the same as the probability of choosing either a red of a blue marble. There are 5+4 out of 15 ways of doing this. The probability is therefore 9/15 = 3/5.
There are 16 marbles total and 7 green ones, so the probability is 7/16.
7/10