We'll if they are 89% it's pretty high
You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
If she is a 41% shooter she will probably score a goal 41 times out of a hundred, but she will probably miss the other 59 times out of a hundred. So the probability that she will miss is 59 out of 100 = 59% = 0.59
10.56% The probability that he misses his first shot is 12%. The probability that he makes the second shot is 88%. The probability of missing the first shot and making the second shot is 12% * 88%, or 0.12*0.88*100.
There is a 10 percent chance that you are gonna throw a 1.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
The probability the shooter makes both shots is .7 * .7 = .49, and the probability of making neither is .3 * .3 = .09. So the probability of making exactly 1 out of 2 is 1 - .49 - .9 = .42, or 42 percent.
You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
There is a 58% chance they are going to miss.
If she is a 41% shooter she will probably score a goal 41 times out of a hundred, but she will probably miss the other 59 times out of a hundred. So the probability that she will miss is 59 out of 100 = 59% = 0.59
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
Steve Nash, plays for the Phoenix Suns, born in Victoria, British Columbia, Canada, is the best clutch free throw shooter in NBA history. However, Dirk Nowitzki has emerged as a very clutch free-throw shooter, making more than 95% of his free-throws that he shoots in the fourth quarter.
10.56% The probability that he misses his first shot is 12%. The probability that he makes the second shot is 88%. The probability of missing the first shot and making the second shot is 12% * 88%, or 0.12*0.88*100.
There is a 10 percent chance that you are gonna throw a 1.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
Ben Wallace
yes
No, not that I ever heard of. It maybe if you are talking to the free throw shooter.