If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
So I guess the counters are numbered 1 through 7, and you pick one of them. There are 7 possibilities, 3 of them are even numbers {2,4,6}, so the probability is 3 out of 7. 3/7 = approx. 42.86%
The probability is 1/2.
depends on how many of the even numbers you have
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
If you chose the number out of an equal numberof odd and even numbers then it would be 50% chance. Like if you chose an odd number out of the numbers from 1 to 100
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
So I guess the counters are numbered 1 through 7, and you pick one of them. There are 7 possibilities, 3 of them are even numbers {2,4,6}, so the probability is 3 out of 7. 3/7 = approx. 42.86%
The probability, or probility, even, is 0 since tere can be no such thing as "choosing red card of the black".
The probability is 1/2.
50%
In base ten, and with no whacky assumptions, the probability that 11 is even is zero.
The probability of rolling an even number on a die is 3 in 6 or 1 in 2. The probability of rolling a prime on a die is 3 in 6 or 1 in 2, but one of those primes is also even. Simply add the probabilities and you find that the probability of rolling an even number or a prime on a die is 5 in 6.
depends on how many of the even numbers you have
Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .
your set of even number x = {2,4,6}, which tells you that 3 out the 6 sides are even. Your probability is 3/6 = 1/2