The answer depends on how many of the 8 things are even and how many are odd. Since this information is not provided it is not possible to answer the question.
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
So I guess the counters are numbered 1 through 7, and you pick one of them. There are 7 possibilities, 3 of them are even numbers {2,4,6}, so the probability is 3 out of 7. 3/7 = approx. 42.86%
The probability is 1/2.
depends on how many of the even numbers you have
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
If you chose the number out of an equal numberof odd and even numbers then it would be 50% chance. Like if you chose an odd number out of the numbers from 1 to 100
So I guess the counters are numbered 1 through 7, and you pick one of them. There are 7 possibilities, 3 of them are even numbers {2,4,6}, so the probability is 3 out of 7. 3/7 = approx. 42.86%
The probability is 1/2.
50%
The probability, or probility, even, is 0 since tere can be no such thing as "choosing red card of the black".
In base ten, and with no whacky assumptions, the probability that 11 is even is zero.
depends on how many of the even numbers you have
The probability of rolling an even number on a die is 3 in 6 or 1 in 2. The probability of rolling a prime on a die is 3 in 6 or 1 in 2, but one of those primes is also even. Simply add the probabilities and you find that the probability of rolling an even number or a prime on a die is 5 in 6.
Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .
your set of even number x = {2,4,6}, which tells you that 3 out the 6 sides are even. Your probability is 3/6 = 1/2