The answer depends on how many of the 8 things are even and how many are odd. Since this information is not provided it is not possible to answer the question.
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If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
So I guess the counters are numbered 1 through 7, and you pick one of them. There are 7 possibilities, 3 of them are even numbers {2,4,6}, so the probability is 3 out of 7. 3/7 = approx. 42.86%
The probability is 1/2.
depends on how many of the even numbers you have