The probability is 4/52*3/51 ~= 0.0045 = 0.45%
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A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
Since there are 4 aces is a normal deck of 52 cards, the probability of drawing an ace is 4 in 52, or 1 in 13.
The probability of drawing two Aces from a standard deck of 52 cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.00452.
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.
The probability of drawing one ace from a deck of 52 cards is 13 to 1 as there are 4 aces in a deck of 52 cards. The probability of then taking another ace is then 17 to 1 as there are now 3 aces in a deck of 51 cards. The total probability for the two events in succession would now be: (13 x 17) to (1 x 1) which is 221 to 1.