That leaves 3 numbers, 15, 16, 17. If you're looking for the probability of drawing an even number it would be 1/3, or 0.333.
If enough cards are drawn it is a certainty. In a single draw, the probability is 0.3846 if you assume that Q is neither odd nor even. If you take Q to be 12, and therefore, even, then the probability increases to 0.4615, approx.
5/13
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
2,4,6,8,10... 5/26
That leaves 3 numbers, 15, 16, 17. If you're looking for the probability of drawing an even number it would be 1/3, or 0.333.
It is 20/52 or 5/13.
If enough cards are drawn it is a certainty. In a single draw, the probability is 0.3846 if you assume that Q is neither odd nor even. If you take Q to be 12, and therefore, even, then the probability increases to 0.4615, approx.
5/13
If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.
2,4,6,8,10... 5/26
The probability is 1/2.
50%
In base ten, and with no whacky assumptions, the probability that 11 is even is zero.
depends on how many of the even numbers you have
The probability of rolling an even number on a die is 3 in 6 or 1 in 2. The probability of rolling a prime on a die is 3 in 6 or 1 in 2, but one of those primes is also even. Simply add the probabilities and you find that the probability of rolling an even number or a prime on a die is 5 in 6.
The probability of drawing a red even card is 5 in 13 (assuming that the face cards are neither even nor odd). The probability of throwing a sum of 11 is 1 in 18. The probability, then, of doing both of these actions, since they are mutually independent, is simply their product, or (5 in 13) times (1 in 18) equals 5 in 234, or about 0.02137.