You have two options:
Tree diagram
or binomial
I choose binomial
3 chooses 2
3*2*1/(2) = 3
3 * .5^2 * .5 = .375
or 37.5%
Or if you want it in the exact order HHT
its .5^3 which is 12.5%
The probability is 0.375
If both tosses are fair, the probability of that outcome is one in four.
The answer is 1/2 , assuming the coin is fair.
Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.
The probability is 2/4 or 4/8 or 1/2. The reason is that if you have 4 identical coins and you flip all of them at once you have half a chance because you could either get all heads, all tails, or a combination.
It is 1/2.
The probability of the first coin landing heads is half (or 1/2). Similarly, the probability of the second and third coins landing heads are also 1/2 in each case. Therefore, the probability of having three heads is: (1/2)(1/2)(1/2) = (1/8)
The probability is 0.375
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
well since the coins have two sides,there is a 50% chance of it landing on heads
The probability of flipping three heads when flipping three coins is 1 in 8, or 0.125. It does not matter if the coins are flipped sequentially or simultaneously, because they are independent events.
The probabilty of you flipping 3 coins and getting all heads or tails is 0.125 or 1/8.
The answer depends on how many coins are flipped, and how often.
p(heads)= 0.5 p(heads)^4= 0.0625
http://wiki.answers.com/Q/If_you_Flip_four_coins_at_once_what_is_probability_of_2_head_and_3_tail" The probability of flipping four coins and getting 2 heads and 3 tails is ZERO 2 heads and 3 tails requires flipping FIVE coins.
0.54 or 0.0625 or 1/16.
If both tosses are fair, the probability of that outcome is one in four.