Q: What is the probability of getting en even and odd number?

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If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.

If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).

50 50 odd or even same probability

The probability that, when rolling three dice none will come up odd is broken down by the probability that on odd roll will occur as an independent event. Rolling the first die has a probability of 3/6 that it will be odd. Rolling the second has the probability of 3/6 that it will be odd. Rolling the third has a probability of 3/6 will be odd. Rolling three and coming up with odd is really the probability that no odd numbers occurred, so therefore an even number DID happen (3/6), and an even number DID happen (3/6), and an even number DID happen (3/6). That's really just 1 - (3/6^3) or simplified 1 - (1/2^3). So therefore the probability that an odd number occurred in 3 die rolls is about 87.5%.

It is 0.5

Related questions

The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.

The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.

If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.

If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).

To answer this problem you first see how many even and odd numbers there are. There are 3 odd and 3 even. so the fraction for even and odd is 3/6 so then in simplified form it is 1/2. If they ask to express the probability as a decimal number it would be .5 or.50

Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .

50 50 odd or even same probability

There are 3 odd numbers, 1, 3 and 5 so the probability of getting an odd number is 3 out of 6 or 1/2. This can also be written as .5 of course.

The probability of rolling an odd number of a standard die is 3 in 6, or 1 in 2, or 0.5.

I'm assuming you multiply the numbers rolled. Thus the rules of even and odd numbers come into play. The only way to get an odd product is to roll two odd numbers. The probability desired is 1 minus the probability of rolling two odd numbers. The odds of rolling an odd number is 1/2. Since the rolls are independent events, the odds of rolling two odd numbers is (1/2)2 = 1/4 So the probability of getting an even product is: 1 - 1/4 = 3/4

the possibles are end less!!

The probability that, when rolling three dice none will come up odd is broken down by the probability that on odd roll will occur as an independent event. Rolling the first die has a probability of 3/6 that it will be odd. Rolling the second has the probability of 3/6 that it will be odd. Rolling the third has a probability of 3/6 will be odd. Rolling three and coming up with odd is really the probability that no odd numbers occurred, so therefore an even number DID happen (3/6), and an even number DID happen (3/6), and an even number DID happen (3/6). That's really just 1 - (3/6^3) or simplified 1 - (1/2^3). So therefore the probability that an odd number occurred in 3 die rolls is about 87.5%.