1 out of 60
The probability of drawing two kings from a single deck of cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.004529.
There is a 1 (one) in 13 (thirteen) chance that you will pull out a queen from a deck of 52 (fifty-two) cards.
A standard 52 cards deck contains 4 kings and 4 tens. Given that the type of the card does not matter, we have a total of 8 valid cards (4 kings + 4 tens) to choose from a 52 cards deck. Hence the probability is 8/52.
there's 13 spades in a standard deck but since we're talkin' two decks.. there's 26 spades out of 104 cards.. so you do 26/104 which reduces to 1:4 aka the probability
1 out of 60
The probability of drawing two kings from a single deck of cards is 4 in 52 times 3 in 51, or 12 in 2652, or 1 in 221, or about 0.004529.
There is a 1 (one) in 13 (thirteen) chance that you will pull out a queen from a deck of 52 (fifty-two) cards.
A standard 52 cards deck contains 4 kings and 4 tens. Given that the type of the card does not matter, we have a total of 8 valid cards (4 kings + 4 tens) to choose from a 52 cards deck. Hence the probability is 8/52.
In a standard deck the probability is 0. There are not two, but 26 cards of the same colour.
It is approx 4.62*10-7.
4 kings in 52 cards then 3 kings in 51 cards 4/52 * 3/51 = .00452488
there's 13 spades in a standard deck but since we're talkin' two decks.. there's 26 spades out of 104 cards.. so you do 26/104 which reduces to 1:4 aka the probability
Two cards are drawn from a pack of 52 cards second card is drawn after replacing the first card. What is the probability that the second card is a king?
The probability of drawing a red two from a standard deck of 52 cards is 2 in 52, or about 0.03846.
0.149
This problem is the type of the probability of A and the probability of B. These events are independent. P(A) and P(B) = P(A) * P(B). In this case these two probabilities are equal; the probability of a king is 4/52. So, the probability of draw king, replace and draw king is 4/52 * 4/52 = 0.00592.