If you mean rolling at least one three, the 1/3.
If you mean exactly one three, then 5/18.
and
If you mean a sum of 3 for the two throws, the answer is 1/18
It is 0.722... recurring.
one fourth
Rolling it once there is a 1 out of 6 chance - because there is 6 numbers on a dice and one of them is three. so rolling it twice would be a 2 out of 12 chance / 0.16 / 16% chance
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
If it is a regular dice then the probability is 3/6 that is 1/2
Because 3/6 of the sides on a number cube have even numbers, the probability of rolling even on one number cube is 1/2(equivalent of 3/6). But since you're rolling twice, you multiply the probability of one by itself (therefore rolling 2 number cubes). So: 1/2x1/2=1/4 The probability of rolling an even number when a number cube is rolled twice is 1/4, 25%, or 1 out of 4.
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
It is 0.722... recurring.
one fourth
Rolling it once there is a 1 out of 6 chance - because there is 6 numbers on a dice and one of them is three. so rolling it twice would be a 2 out of 12 chance / 0.16 / 16% chance
2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.
If it is a regular dice then the probability is 3/6 that is 1/2
50 percent
The probability is 1/6.
To find the probability of rolling an even number on the first roll and a 1 on the second roll with a single die, we first note that the even numbers on a die are 2, 4, and 6. Thus, the probability of rolling an even number on the first roll is 3 out of 6, or 1/2. The probability of rolling a 1 on the second roll is 1 out of 6. Therefore, the combined probability is (1/2) * (1/6) = 1/12.
It is 1/36.
That depends on whether you roll it twice or not...