It is 1/6.
The probability of rolling a 5 on a roll of a single number cube is 1/6 (0.1666) as there is only one number 5 on a total of 6 sides on the cube.
1 out of six
5/6 = (83 and 1/3) percent
There is insufficient information on the shape of the spinner.
It is (5/6)^72*(1/6) = 0.0000003317, approx.
The probability of rolling a 5 on a roll of a single number cube is 1/6 (0.1666) as there is only one number 5 on a total of 6 sides on the cube.
1 out of six
P(not 5) = 1,2,3,4&6. out of six faces. Hence P(Not 5) = 5/6 = 0.8333 or 1 - P(5) = 1 - 1/6 = 5/6 = 0.8333 NB '1' being the probability of any number out of the '1'. ( 6 out of 6).
It is 5/6
impossible.
1/24
The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.
5/6 = (83 and 1/3) percent
1 6th and 1 half
1 in 6 = rolling a 2 5 in 6 = not rolling a 2
It is 1/6.
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.