-- There are (2 x 2 x 2 x 2) = 16 possible outcomes of four tosses.
-- There are three successful cases:
-- So the probability is 3/16 or 18.75% .
For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.
lands heads up
The probability of the coin flip being heads or tails is 100%.
Since it is a fair coin, the probability is 0.5
One in six. One in two.
For each toss, the probability that it'll land heads up is 1/2 So 1/2 * 1/2 * 1/2 = 1/8, or .125 There is a 12.5% chance that it will land heads-up all 3 times.
lands heads up
The probability of the coin flip being heads or tails is 100%.
No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.
If it is a fair coin, the probability is 1/2.
1/2, or 50% since you are only asking what the probability of the last outcome is.
Since it is a fair coin, the probability is 0.5
One in six. One in two.
It means just what it seems to -- someone tosses a coin up and you try to guess which side will be facing up when it lands. "Heads" is the side with the person's face on it and "tails" is other side.
If p is the probability that any one toss lands on "heads", the probability that exactly 4 toss out of 8 lands on head is this: p^4 * (1-p)^4 * C(4,8) Where C(k,n) is an old notation for n! / ( k! * (n-k)! ) So C(4,8) = 8! / ( 4! * 4!) = 8*7*6*5 / 24 = 70 If your coin is well balanced, p is 50% and you get your answer: (0.5)^8 * 70 = 70/256 =~ 27,34%
1/2 (equal to 0.5, or 50%).
50%