The answer depends on whether the question is in the context of a deck of playing cards or some other collection, whether or not the cards are replaced after picking, whether the cards are selected at random. Since there is no information on any of these aspects, it is not possible to give a useful answer to the question.
The probability that all four of the cards are different suits is 13/17 * 13/25 * 13/49 = 2197/20,825 or 10.54982%.
The probability of inserting all four cards in the correct envelops is 1/24.
There are four 9's and four jacks. If you can use all of them, you can use 8 out of 52 cards. The probability of drawing one of these cards is therefore 8/52 = 0.1538 or a 15.38 % chance.
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
13/24 * 12/23 * 11/22 * 10/21 1st 2nd 3rd 4th = .06728 or 6.72877%
The probability that all four of the cards are different suits is 13/17 * 13/25 * 13/49 = 2197/20,825 or 10.54982%.
The probability of inserting all four cards in the correct envelops is 1/24.
There are four 9's and four jacks. If you can use all of them, you can use 8 out of 52 cards. The probability of drawing one of these cards is therefore 8/52 = 0.1538 or a 15.38 % chance.
For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.For an ordinary deck of cards, the probability is 1. All decks of playing cards contain 3s.
The probability of five cards being four cards from one suit and one card from another suit is the same as the probability of drawing four cards from one suit multiplied by the probability of drawing one card from another suit, multiplied by 5 (for each of the possible positions this other card can be drawn in). The probability of drawing four cards from one suit is 12/51 x 11/50 x 10/49. The probability of drawing a fifth card from another suit is 39/48. All these numbers multiplied together (and multiplied by 5) come to 0.0429. So the probability of drawing a hand of five cards with four cards from one suit and one card from another is 5.29%
There are four 8's, four 7's, four 6's, four 5's, four 4's, four 3's, four 2's, and four aces. Add all of them up and you get a total of 32 cards so the probability is 32/52 which reduces to 16/26 which reduces to 8/13= Probability of the above mentioned outcome.
13/24 * 12/23 * 11/22 * 10/21 1st 2nd 3rd 4th = .06728 or 6.72877%
The probability is 7,893,600/311,875,200 = 0.0253
Very low (less than 0.00000000001%)
As described, the deck contains 52 cards, numbered 1 to 13, four times in four colors, red, blue, black, and green. The probability of drawing more than one red card with the same number on it is zero.
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
Answer