Wiki User
∙ 15y agoWell you see black people are useless. Whoever made the black child is obviously an ape of some sort.
Wiki User
∙ 15y agoThe answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
The probability is one half.
0.5
Excluding jokers, the probability is 1 in 2.
The probable phenotype of the offspring would be black, as black color is dominant over chestnut color. The genotype of the offspring would be heterozygous for black (Bb), since one parent is homozygous black (BB) and the other is homozygous chestnut (bb).
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
All offspring would inherit one black allele and one white allele, resulting in a heterozygous genotype. Therefore, all eight offspring would likely have black fur, as the black color allele is dominant over white in guinea pigs.
In a monohybrid cross with black as dominant (B) and white as recessive (b), the probability of an offspring being black is 75% (3/4) and the probability of being white is 25% (1/4) according to the Punnett square ratios.
To have offspring with black fur, both parent dogs must carry the gene for black fur. This gene is usually dominant, meaning that if at least one parent carries it, there's a high chance the offspring will have black fur. If both parents have black fur, then their offspring will also have black fur.
To determine the genotype of a white ram, breed him with black females. Black females are homozygous recesive for the black trait, a. If the ram is homozygous dominant, all offspring will be white (and heterozygous). If the ram is heterozygous, approximately half of it's offspring will be white and half will be black.
100% because BB is dominant over bb and all the crosses make Bb
The answer depends on how big the litter is: as the litter size increases the probability of one black fur increases. But as it gets larger still, the probability falls because two or more black furs become more probable.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
The possible genotypes of the offspring will be 50% heterozygous black (Bb) and 50% homozygous black (BB). The phenotypes of the offspring will all be black, as black coat color is dominant over white.
You would expect 50% of the offspring to have black bodies. This is because the offspring will inherit one allele for black body color from the black parent, and one allele for gray body color from the heterozygous gray parent. The black allele is dominant over the gray allele.
my doe is black and my buck is brown. They have 3 brown offspring and 2 black. Actually one bunny is brown with black. So i can say that it is 50-50