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the punnett square
It's used commonly to estimate the traits of a child of two parents. For example, the probability of the child having blue eyes, or curly hair, or even having genetic disease.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that children's genders are independent events then, given that the probability of a girl is approx 0.48.
The probability is 2 - 6
It depends on the context: if you select a child at random from a girls' school, the probability is 0, while if it is at a boys' school it is 1!
No probability. Neither parent has an "A" for the child to inherit to make an "AB".
Bad luck?
That depends on whether the man in his 30s inherited HD from his mother. If he did not, the chances are zero. If he did, the chances are 50-50 for each child that they will inherit from him.
the punnett square
It's used commonly to estimate the traits of a child of two parents. For example, the probability of the child having blue eyes, or curly hair, or even having genetic disease.
Not always. It depends if the individual is a hybrid- meaning they have both the dominant and the recessive gene. They can pass on the recessive gene instead of the dominant one, and assuming the other parents also passes on the recessive gene, the child will not inherit the disease.
same probable as the first child having it. By doing the punnet square, they are both recessive for the disease. There is a 25% chance that the child will get the disease.
There is no simple answer to the question because the children's genders are not independent events. They depend on the parents' ages and their genes.However, if you assume that children's genders are independent events then, given that the probability of a girl is approx 0.48.
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
For the case where the disease is a recessive trait (more likely), the probability is 1/2 that they will carry the diseased gene but not show it. If the disease is a dominant trait, the probability is 1/2 that they will get it and show it. Having said that, in the recessive case, if both parents are carriers, then there is a 1/4 case the child will get it from both and then show the disease. I have answered regarding genetically-transmitted diseases. Mental illness and other forms of "disease" will be different.
A child inherits PKU if both parents are carriers of the gene mutation that causes the condition. When both parents are carriers, there is a 25% chance with each pregnancy that the child will inherit two copies of the mutated gene and have PKU.
Both the father and mother of a child have to carry a mutation in the ASPA gene in order for the child to inherit Canavan disease. If both parents are carriers, each naturally conceived child has a 25% chance of having Canavan. Although most common in people of Ashkenazi Jewish descent, there are upwards of 70 mutations of the gene that have been identified so far, and they can occur in individuals from any ethnic background.