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How many Wednesdays are in a year?
Since there are 52 weeks in a year usually there are 52 Wednesdays in a year. If the year starts on a Wednesday, then there are 53 Wednesdays. If it is a leap year that starts on a Tuesday, it will have 53 Wednesdays.
What is the probability that a leap year selected at random would contain 53 days Option a) 17 b) 27 c) 112 d) 14?
None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!
What is the probability that a leap year selected at random will contain you 53 Sundays II 53 Thursdays?
A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.
What is probability that a leap years selected at random will contain 53 Sundays?
probability = 2/7 to be exact, 28/97 (about 28.87%)
How many Wednesdays are there this year?
Oh, dude, there are 52 Wednesdays in a year, like, every year. It's like clockwork, man. So, if you're looking to plan your midweek shenanigans, you've got plenty of hump days to choose from. Enjoy!
How many Wednesdays are in a year?
Since there are 52 weeks in a year usually there are 52 Wednesdays in a year. If the year starts on a Wednesday, then there are 53 Wednesdays. If it is a leap year that starts on a Tuesday, it will have 53 Wednesdays.
Are there ever more than 52 Wednesdays in a calendar year?
Yes. If any year starts on a Wednesday or a leap year starts on a Tuesday, there are 53 Wednesdays in a year.
How many Wednesdays were there in 2008?
There were 53 Wednesdays in 2008. 2008 was a leap year that began on Tuesday and ended on Wednesday, so there were 53 Tuesdays and Wednesdays, and 52 each of every other day of the week. == ==
How many Wednesdays in 1952?
There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.
What is the probability that a leap year selected at random would contain 53 days Option a) 17 b) 27 c) 112 d) 14?
None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!
What is probability of non-leap year has 53 Sundays?
The year MUST start on a Sunday. For a leap year, it can start on Saturday or Sunday. In any period of 400 years there are 303 non-leap years, of which 43 begins and ends with a Sunday, and there are 97 leap years, of which 28 begins with a Saturday or a Sunday. So the probability in a non-leap year is 43/303, or 14.2%. And the probability in a leap year is 28/97, or 28.9%
What is the probability of getting 53 Fridays in a leap year?
A leap year is 52 weeks plus 2 days. That means that 2 days have 53 instances. So there is a 2/7 chance that there will be 53 Fridays. There is absolutely no chance that there are 54 Sundays, since 53 is the most you can have. Good luck. The exact probability is 28/97, which is about 28.87%.
Were there 52 Wednesdays in 2009?
Yes there were 52 Wednesdays in 2009. In a regular year there are about 365 days, so there will be one day of the week that will occur 53 times, two days of the week in a leap year. 365 days in a regular year divided by 7 is 52 with a remainder of one, meaning one of the days of the week has to occur an extra time. Leap year has a remainder of two, so two days will occur 53 times.
Why is there 53 Thursdays and not 53 other days in the year?
A 365 day year is one week and one day. That means that the first and last day of the year are the same day of the week. So whatever day the year starts on, will have 53 of them and all other days will have 52. If a year starts on a Thursday, then there will be 53 Thursdays in that year. In the case of a leap year. The first and second day of the year will have 53 occurrences. So if a leap year starts on a Wednesday or Thursday there will be 53 Thursdays. If it starts on a Wednesday, there will also be 53 Wednesdays, and if it starts on a Thursday, there will also be 53 Fridays.
What is the chance that a leap year selected at random will contain 53 Saturdays?
Since you are selecting only among leap years, either the first or the second day of the year would have to be a Saturday, so you have two chances out of seven (a probability of 2/7) that there are 53 saturdays.
What is the probability that a leap year selected at random will contain you 53 Sundays II 53 Thursdays?
A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.
What is probability that a leap years selected at random will contain 53 Sundays?
probability = 2/7 to be exact, 28/97 (about 28.87%)
