The total number of days in a leap year is 366. Then, if we want to determine the probability of 53 Wednesdays occurring in a leap year, we write 53 / 366.
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Since there are 52 weeks in a year usually there are 52 Wednesdays in a year. If the year starts on a Wednesday, then there are 53 Wednesdays. If it is a leap year that starts on a Tuesday, it will have 53 Wednesdays.
None of them. The probability of an event cannot be greater than one. Besides, every leap year will have 366 days, not 53!
A Leap year has 366 days. in which you have 52 weeks and 2 days. the 2 days may be sun,Mon mon,Tue tue,wed wed,THu, thu,Fri FRi,SAT sat,sun so you have 7 options among which 2 u can choose.. so the answer is 2/7 for having 53 Sundays. The probability of having 53 Thursdays is also 2/7. The probability of having either 53 Sundays or 53 Thursdays is 4/7.
probability = 2/7 to be exact, 28/97 (about 28.87%)
Oh, dude, there are 52 Wednesdays in a year, like, every year. It's like clockwork, man. So, if you're looking to plan your midweek shenanigans, you've got plenty of hump days to choose from. Enjoy!