It is 6/36 = 1/6
The answer depends on how many times it is rolled.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on the sum of WHAT!
Six. Red1 + Blue6, R2+B5, R3+B4, R4+B3, R5+B2 and R6+B1,
Total number of outcomes are 6*6 or 36. There is 1 way to get a 2; which is 1,1. So, the probability is 1/36.
The answer depends on how many times it is rolled.
There are only three possible ways of rolling 4: 1/3, 2/2 and 3/1. There are 36 possible rolls so probability is 3/36 or 1/12
The probability of rolling a sum of 8 on one roll of a pair of dice is 5/36.The probability of not rolling a sum of 8 on one roll of a pair of dice is 31/36.The probability of rolling a sum of 8 twice on two rolls of a pair of dice is(5/36)(5/36) = (5/36)2 .The probability of rolling first a sum of 8 and then rolling a sum that is not 8 on thesecond roll is (5/36)(31/36).The probability of rolling a sum that is not 8 on the first roll and rolling a sum of 8in the second roll is (31/36)(5/36).So The probability of rolling a sum of 8 at least one of two rolls of a pair of dice is(5/36)2 + (5/36)(31/38) + (31/36)(5/36) = 0.258487654... ≈ 25.8%.
On a normal cube, the probability is 0. If there are more than 1 cubes, the answer depends on how many are being rolled for each sum.
The answer depends on the sum of WHAT!
Six. Red1 + Blue6, R2+B5, R3+B4, R4+B3, R5+B2 and R6+B1,
Total number of outcomes are 6*6 or 36. There is 1 way to get a 2; which is 1,1. So, the probability is 1/36.
68
8 is the same as the sum of the digits of its cube, 512.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
The probability is 21/36 = 7/12