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We assume a 6 sided fair die. Now, note that the probability of rolling any number is independent of the probability of the outcome on the next role of the die. In probability terms we say the two events are independent this implies that is we look at the probability of A and the probability of B the probability of A and B is P(A)xP(B) Since we are look at the probability of a 5 and there are 6 possible outcomes, the probability of a 5 is 1/6 and a similar argument tells us the probability of a 2 is 1/6. Now, since they are independent, the probability of a 5 AND a 2 is 1/6 x 1/6=1/36 If you want to consider dice with different shapes and fewer than 6 numbers, the answer will change. I have considered only a 6 sided fair die since if one understands how this works, one can generalize to other scenarios. The commonly used die is called a cubic polyhedron. Dice come as many different polyhedra and these make for interesting probability questions.

Q: What is the probability that you roll a 5 and a 2?

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The probability that you roll a 3 or a 5 on one or both dice is 20/36 = 5/9

If you roll the die often enough the probability is near enough 1 so as to make no difference. On a single roll, the probability is 1/2.

Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.

The probability is 26/36 = 13/18.

It is 0.9034, approx.

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The probability that you roll a 3 or a 5 on one or both dice is 20/36 = 5/9

The probability that you roll a multiple of 3 (3 and 6) in a fair die is: P(3 or 6) = 2/6=1/3 = 0.333... ≈ 33.3%.The probability that you roll a multiple of 5 (5) is: P(5) = 1/6.The probability that you roll a multiple of 3 or 5 is: P(3 or 6 or 5) = 2/6 + 1/6 = 1/2 = 0.50 = 50%

1/6 for all 6 numbers.-- On the first roll, the probability of a ' 1 ' is 1/6 .-- On the second roll, the probability of a ' 2 ' is 1/6 .-- On the third roll, the probability of a ' 3 ' is 1/6 .-- On the fourth roll, the probability of a ' 4 ' is 1/6 .-- On the fifth roll, the probability of a ' 5 ' is 1/6 .-- On the sixth roll, the probability of a ' 6 ' is 1/6 .So the probability of rolling 1 - 2 - 3 - 4 - 5 - 6 in six rolls is (1/6)6 = 0.000021433 = 0.0021%

If you roll the die often enough the probability is near enough 1 so as to make no difference. On a single roll, the probability is 1/2.

Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3

Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.

The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .

The probability is 26/36 = 13/18.

It is 0.9034, approx.

There are 6 outcomes on a die roll (1,2,3,4,5,6); 5 & 6 constitutes 2 of them so the probability is 2/6 or 1/3.

It is (1/2)*(5/6) = 5/12

If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.If you roll the die often enough, the probability is 1 - a certainty.On a single roll, the probability is 1/6.