There is a 1/6 chance of rolling a 4 on a fair die, and a 1/2 chance of a fair coin landing heads up. Multiply 1/6 X 1/2. The probability of both happening is 1/12.
50-5-
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
Since it is a fair coin, the probability is 0.5
It is 0.5
50-5-
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
The probability that a coin will land on heads - at least once - in six tosses is 0.9844
Since it is a fair coin, the probability is 0.5
Since it is a certainty that a coin must land on either heads or tails, the probability must be 1.
50%
It is 0.5
No, when you toss a coin there is a 50 percent chance it will land heads up.
Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.Prob(Cube = 4) = 1/6Prob(Coin = H) = 1/2.
the probability is actually not quite even. It would actually land heads 495 out of 1000 times because the heads side is slightly heavier
The probability of a coin landing on heads is 0.5. It does not matter which toss it is, and it does not matter what the toss history was.
1/2 or 0.5