I'm assuming your question is the same as this: "If 2 dice are rolled, what is the probability of not getting 1 on either die?"
To answer this question, we need to look at what IS possible. If I'm 2 rolling normal, fair dice, then I have equal probability of getting each of the numbers 1-6 on either die. If I'm trying to NOT get 1, then I want to get any of the numbers 2-6 on both dice. This gives me 10 desired outcomes (5 numbers * 2 dice) out of 12 possible outcomes (6 numbers * 2 dice), so the probability is 10/12, which simplifies to 5/6.
1/6 A dice has six faces. And '2' is on one if its faces. So the probability of getting a 2 on a dice is 1 over 6.
The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
It is (1/2)*(1/6) = 1/12
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
1/6 A dice has six faces. And '2' is on one if its faces. So the probability of getting a 2 on a dice is 1 over 6.
The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
The probability of getting a 2 or 12 on two dice is 2 in 36, or 1 in 18.
The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.The only number less than 3 that you can get with two dice is 2. The probability of getting a 2 is 1/36.
.3
1 out of 2.
It is a probability of a 1 in 6
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
It is (1/2)*(1/6) = 1/12
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
It is 2/6 = 1/3
It is 1/36.