When sodium hypochlorite (NaOCl) is added to lead(IV) oxide (PbO2), a redox reaction occurs. NaOCl acts as an oxidizing agent, and PbO2 can be reduced to lead(II) oxide (PbO) in this process. The overall reaction typically produces lead(II) oxide and sodium chloride (NaCl), along with the release of oxygen. The exact conditions and concentrations can influence the specific products formed.
9x+7
7
The way to write that is 2X+5
one number will be added
(78 x 45) + (93 x 64) = 3510 + 5952 = 9462
The product for the reaction between PbO2 and O2 is PbO2.
When NaOCl (sodium hypochlorite) and PbO2 (lead dioxide) are mixed, a redox reaction occurs where sodium hypochlorite is reduced to chloride ions while lead dioxide is oxidized to lead(IV) chloride. The overall reaction can be represented as: 2NaOCl + PbO2 -> 2NaCl + PbCl4 + O2
Yes, NaOCl is an oxidizing agent.
The traditional name for PbO2 is lead dioxide.
Lead dioxide (PbO2) is typically a dark brown or black color.
PbO2 is lead(IV) oxide.
Lead Dioxide or Lead IV Oxide
The KI NaOCl mixture will turn yellow upon the addition of NaOCl due to the oxidation of iodide ions to iodine.
First , its NaOCl, with a lowercase L, not an i. There are 12 atoms in 4 formula units of NaOCl.
PbO2 is a stronger oxidizing agent compared to PbO because PbO2 has a higher oxidation state of +4 for lead, allowing it to accept more electrons during a redox reaction. This makes PbO2 more likely to cause other substances to be oxidized.
2PbS + 3O2 ----> 2PbO + 2SO2
The formula for plumbous oxide is PbO.