Assuming the spaces would have held plus signs...
(0.5n + 5) times 2 is n + 10
(n + 10)(10n + 7) is 10n^2 + 107n + 70
You can either add three to that (+ 73) or multiply it by three
30n^2 + 321n + 210
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The product of 3 and 7 is 21
7 minus the product of v and 3
-4
3/7
7)441 7)63 3)9 3)9 3)3 = 1 Hence 441 is the product of 7x7x3x3 = 7^(2) x 3^(2) = (7 x3)^(2) = 21^(2)