Assuming the spaces would have held plus signs...
(0.5n + 5) times 2 is n + 10
(n + 10)(10n + 7) is 10n^2 + 107n + 70
You can either add three to that (+ 73) or multiply it by three
30n^2 + 321n + 210
The product of 3 and 7 is 21
7 minus the product of v and 3
-4
3/7
7)441 7)63 3)9 3)9 3)3 = 1 Hence 441 is the product of 7x7x3x3 = 7^(2) x 3^(2) = (7 x3)^(2) = 21^(2)
The product of 3 and 7 is 21
7 minus the product of v and 3
seven minus the product of v and 3 would be as it sounds. 7- because it says seven minus the product, product means multiply so then v and 3 so then it is 7-3v or v3
The difference of 7 and the product of 30 is calculated by subtracting the product of 30 from 7. The product of 30 is 30 multiplied by 7, which equals 210. Therefore, the difference of 7 and the product of 30 is -203.
-4
3/7
7-(u+3)
"Product" is a binary operation. You cannot have a product of 3: it has to be the product of 3 and another number.
As a product of its prime factors: 3*3*5*5*7*7 = 11025
As a product of its prime factors: 3*7*7 = 147
7)441 7)63 3)9 3)9 3)3 = 1 Hence 441 is the product of 7x7x3x3 = 7^(2) x 3^(2) = (7 x3)^(2) = 21^(2)
7 * 2/3 = 14/3 or 42/3